Talk:Weightlessness
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I thought that when using SI units it was unnecesary to put in these constants as the system is designed around them --sodium
SI doesn't eliminate the constant in this case. It does for F=ma, for instance (this is F=kma in other unit systems) but not for F=k/r^2. In this case k=-G M1 M2, where G is 'big G', the gravitational constant, and M1 and M2 are the masses of the gravitating bodies. -- DrBob
How does a wood block experience anything? -phma
- Presumably it does so in ways that only another wood block could understand.
You are obviously taking an analogy (i.e. the woodblock) too seriously. This means that you are either very slow and stupid, or else you are so logical that the concept of metaphor is simply beyond the comprehension of your over-developed brain.
- It would be preferable if you would avoid personal attacks in this forum. Especially when you can't manage to add your own signature. — RJH 17:53, 13 Apr 2005 (UTC)