Talk:Lagrange inversion theorem
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What about this:
- <math>
\left.
g(z) = a
+ \sum_{n=1}^{\infty}
\frac{d^{n-1}}{(dw)^{n-1}}
\left( \frac{(w-a)^n}{(f(w) - b)^n} \right)
\right|
_{w = a}
{\frac{(z - b)^n}{n!}}
<math>
∞ dn-1 / (w - a)n \ | (z - b)n
g(z) = a + ∑ ------ | ----------- | | --------
n=1 (dw)n-1 \ (f(w) - b)n / | n!
| w=a
--Edmund 02:23 Feb 22, 2003 (UTC)
Yup, the TeX is correct now. AxelBoldt 20:45 Mar 2, 2003 (UTC)