Durand Township, Minnesota
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Durand Township is a township located in Beltrami County, Minnesota. As of the 2000 census, the township had a total population of 175.
Geography
According to the United States Census Bureau, the township has a total area of 47.5 km² (18.3 mi²). 39.1 km² (15.1 mi²) of it is land and 8.4 km² (3.2 mi²) of it is water. The total area is 17.72% water.
Demographics
As of the census2 of 2000, there are 175 people, 76 households, and 51 families residing in the township. The population density is 4.5/km² (11.6/mi²). There are 82 housing units at an average density of 2.1/km² (5.4/mi²). The racial makeup of the township is 94.29% White, 0.00% African American, 5.14% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.57% from two or more races. 0.00% of the population are Hispanic or Latino of any race.
There are 76 households out of which 26.3% have children under the age of 18 living with them, 56.6% are married couples living together, 10.5% have a female householder with no husband present, and 31.6% are non-families. 27.6% of all households are made up of individuals and 6.6% have someone living alone who is 65 years of age or older. The average household size is 2.30 and the average family size is 2.81.
In the township the population is spread out with 21.7% under the age of 18, 7.4% from 18 to 24, 22.9% from 25 to 44, 37.1% from 45 to 64, and 10.9% who are 65 years of age or older. The median age is 44 years. For every 100 females there are 86.2 males. For every 100 females age 18 and over, there are 90.3 males.
The median income for a household in the township is $39,375, and the median income for a family is $43,438. Males have a median income of $32,500 versus $22,813 for females. The per capita income for the township is $22,886. 7.3% of the population and 0.0% of families are below the poverty line. Out of the total population, 0.0% of those under the age of 18 and 20.0% of those 65 and older are living below the poverty line.