Alexander, Iowa
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Alexander is a city located in Franklin County, Iowa. As of the 2000 census, the city had a total population of 165.
Geography
Alexander is located at 42°48'17" North, 93°28'39" West (42.804760, -93.477395)Template:GR.
According to the United States Census Bureau, the city has a total area of 11.1 km² (4.3 mi²). 11.1 km² (4.3 mi²) of it is land and none of it is covered by water.
Demographics
As of the censusTemplate:GR of 2000, there are 165 people, 79 households, and 48 families residing in the city. The population density is 14.9/km² (38.6/mi²). There are 88 housing units at an average density of 7.9/km² (20.6/mi²). The racial makeup of the city is 96.36% White, 0.00% African American, 0.00% Native American, 0.00% Asian, 0.00% Pacific Islander, 3.64% from other races, and 0.00% from two or more races. 3.64% of the population are Hispanic or Latino of any race.
There are 79 households out of which 24.1% have children under the age of 18 living with them, 55.7% are married couples living together, 3.8% have a female householder with no husband present, and 38.0% are non-families. 35.4% of all households are made up of individuals and 27.8% have someone living alone who is 65 years of age or older. The average household size is 2.09 and the average family size is 2.59.
In the city the population is spread out with 17.0% under the age of 18, 7.3% from 18 to 24, 24.2% from 25 to 44, 24.8% from 45 to 64, and 26.7% who are 65 years of age or older. The median age is 46 years. For every 100 females there are 87.5 males. For every 100 females age 18 and over, there are 95.7 males.
The median income for a household in the city is $31,250, and the median income for a family is $33,750. Males have a median income of $27,344 versus $20,833 for females. The per capita income for the city is $14,995. 9.3% of the population and 6.3% of families are below the poverty line. Out of the total population, 0.0% of those under the age of 18 and 11.3% of those 65 and older are living below the poverty line.