Talk:Peltier-Seebeck effect
|
|
Template:Oldpeerreview The first line of the description is incorrect. It was first discovered by Thomas Johann Seebeck in 1821. Not by Peltier in 1884. Seebeck was not even alive anymore in 1884. He died in 1881.
- I saw two pages that said 1821, but this page [1] (http://www.nanothermel.org/public_main.htm) says 1823. I intend to add more to this article. Omegatron
"Electrons flow from the hot end to the cold end."
I am not so sure this is true. I think it depends on the type of conductors, so I am taking it out for now. Feel free to put it back if you know it is true. Omegatron
- It is true in metals. Apparently not in semiconductors, in which "positive particles" - holes - are free to flow. I have expanded on it a lot now, though. (Great... now I'm talking to myself...) - Omegatron
Just to make sure people know, I redirected thermoelectricity to here, although there might be other forms besides the peltier-seebeck kind?
- I changed this back to a non-redirect, since there is also vacuum tube thermoelectricity. - Omegatron
Please double-check the polarity of my voltmeter in the diagram. I think it is right, but i am not terribly qualified. - Omegatron
Did Seebeck discover the voltage difference first or the current loop/compass first? - Omegatron 17:09, Apr 2, 2004 (UTC)
- <math>V = \int_{T_1}^{T_2} (S_B - S_A) \, dT<math>
I would like to show that these are functions of T, but
- <math>V = \int_{T_1}^{T_2} (S_B(T) - S_A(T)) \, dT<math>
- <math>V = \int_{T_1}^{T_2} (S_{BT} - S_{AT}) \, dT<math>
- <math>V = \int_{T_1}^{T_2} (S_{B\,T} - S_{A\,T}) \, dT<math>
- <math>V = \int_{T_1}^{T_2} (S_{B_T} - S_{A_T}) \, dT<math>
are all ugly. - Omegatron 20:25, Jul 5, 2004 (UTC)
Phonon drag picture
I forgot which one it was but, why did you take off the change carrier diffusion/phonon drag picture? lol, I would not have read that paragraph or two if the picture didn't catch my attention. --Mac Davis 11:13, 9 Jan 2005 (UTC)
Seebeck_effect.png
- The flame and the metal bar? I don't think it is accurate, after thinking about it. The first explanation I heard said that hot electrons would diffuse through the metal bar, which made sense to me, and explained the basics of how heat could generate electric current. So I drew that picture. Then I read more into it, and the cold electrons diffuse in the opposite direction in roughly equal quantities. The imbalance between the two is what actually causes the net electric current, and is caused by the phonon drag and scattering. So, since the picture only shows hot electrons diffusing, it's not accurate. I could make a more accurate one if you could describe what it should look like. I don't really understand phonons and have no idea how to draw phonon drag. :-) - Omegatron 18:42, Jan 9, 2005 (UTC)
Pyroelectricity
Is pyroelectricity the same phenomenon as the seebeck effect?
- I don't think so. One is in metals and one is in crystals. But I am no expert. - Omegatron 00:15, Feb 12, 2005 (UTC)