Talk:Boson

Many scientists determine bosons and fermions after theit spin value without explaining what is a cause for existing of this difference. Really, most of them know that the spin is a result of their inner motion. Some of this motions are determined by common coordinate, but others are determined by martices (bi-spinors) .As different common coordinates are commutative, then their inner oscillations along different oxes are independent and therefore they have a whole number h-bar spin. But other inner oscillations, which are determined by bi-spinors, which are no commutative, their oscillations along different oxes are strongly correlated and therefore they have a half number of h-bar spin. Consequently, if the inner oscillations are determined by commom coordinates, then their oscillations along differetn oxes are independent, then these excitations are bosons and if the inner oscillations are determined by bi-spinors, then their oscillations along differetn oxes are dependent, then these excitations are fermions.

So in a result of its inner motion the electric point-like electric charge make the own electric and magnetic fields of micro particle, then all fermions have zero values of electric intensity of own electric field in its moment plases and the double values of magnetic intensity of own magnetic fieldin some point and all bosobs have equal values of electric and magnetic intensities of their own electric and magnetic fields. Therefore the giromagnetic ratio of the magnetic dipole moment to the angular mechanical moment of the fermions are two times greater then this giromagnetic ratio fot their orbital boson motion.

Corrections

I corrected a few mistakes in the article. For the record, Cooper pairs aren't bosons, since they can't meaningfully be considered as particles. _R_ 12:30, 7 Sep 2004 (UTC)

which is the defining property?

Please see the discussion at Talk:Fermion on whether spin or symmetry is the defining property of fermions and bosons. Fpahl 06:19, 8 Oct 2004 (UTC)

Bosons with even integer spin

We have all noticed that spin is described as being a multiple of hbar/2. I thought that it would be better to set this value to a constant giving,

hdot = hbar/2 = 5.2728584118222738157569629987­554e-35 J.s

But now the equations for spin did not work with hdot, so I had to correct them.

Here are the corrected equations,

|sv| = sqrt(s(s + 2)) * hdot

and

Sz = ms.hdot

where,

sv is the quantized spin vector,

|sv| is the norm of the spin vector,

s is the spin quantum number, which can be any non negative integer,

Sz is the spin z projection,

ms is the secondary spin quantum number, ranging from -s to +s in steps of two integers

For spin 1 particles this gives:

|sv| = sqrt(3).hdot and Sz = -hdot, +hdot

For spin 2 particles this gives:

|sv| = sqrt(8).hdot and Sz = -hdot, 0, +hdot

Now that the spin equations have been corrected, the definitions for fermions and bosons are incorrect, and must be redefined as follows.

Fermions are particles that that have an odd integer spin.

Bosons are particles that have an even integer spin.

Would these redefinitions have any other effects on the Standard Model?

Can these redefinitions explain any currently unexplained phenomena?

Are there any experiments that could confirm or refute these claims?

I would like eveyone to have a good think about this, and give me your objections to it, or even data to support it.