Fibonacci number program
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In many beginning computer science courses, an introduction to the concept of recursion often includes a program to calculate and print Fibonacci numbers (or computing the factorial of a number). In general, however, a recursive algorithm to compute Fibonacci numbers is extremely inefficient when compared to other algorithms, such as iterative or matrix equation algorithms.
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Common Lisp
Calculating fibonacci through Lucas' formula
(defun fib (n)
(cond
((= n 0) 0)
((or (= n 1) (= n 2)) 1)
((= 0 (mod n 2)) (-
(expt (fib (+ (truncate n 2) 1)) 2)
(expt (fib (- (truncate n 2) 1)) 2)))
(t (+ (expt (fib (truncate n 2)) 2)
(expt (fib (+ (truncate n 2) 1)) 2)))))
(fib (parse-integer (second *posix-argv*))) ;
Haskell examples
Lazy infinite list
module Main where
import System.Environment
fibo = 1 : 1 : zipWith (+) fibo (tail fibo)
main = do
args <- getArgs
print (fibo !! (read(args!!0)-1))
Perl examples
One example
#! /usr/bin/perl
use bigint;
my ($a, $b) = (0, 1);
for (;;) {
print "$a\n";
($a, $b) = ($b, $a+$b);
}
Binary recursion, snippet
sub fibo;
sub fibo {$_ [0] < 2 ? $_ [0] : fibo ($_ [0] - 1) + fibo ($_ [0] - 2)}
Runs in Θ(F(n)) time, which is Ω(1.6n).
Binary recursion with special Perl "caching", snippet
use Memoize;
memoize 'fibo';
sub fibo;
sub fibo {$_ [0] < 2 ? $_ [0] : fibo ($_ [0] - 1) + fibo ($_ [0] - 2)}
Iterative, snippet
sub fibo {
my ($n, $a, $b) = (shift, 0, 1);
($a, $b) = ($b, $a + $b) while $n -- > 0;
$a
}
Command line iterative
perl -Mbigint -le '$a=1; print $a += $b while print $b += $a'
PostScript example
Iterative
20 % how many Fibonacci numbers to print
1 dup
3 -1 roll
{
dup
3 -1 roll
dup
4 1 roll
add
3 -1 roll
=
}
repeat
Stack recursion
This example uses recursion on the stack.
% the procedure
/fib
{
dup dup 1 eq exch 0 eq or not
{
dup 1 sub fib
exch 2 sub fib
add
} if
} def
% prints the first twenty fib numbers
/ntimes 20 def
/i 0 def
ntimes {
i fib =
/i i 1 add def
} repeat
Python examples
Recursion
def fib(n):
if n < 2:
return n
else:
return fib(n - 1) + fib(n - 2)
Generator
def fib():
a, b = 0, 1
while True:
yield a
a, b = b, a + b
Matrix equation
def mul(A, B):
a, b, c = A
d, e, f = B
return a*d + b*e, a*e + b*f, b*e + c*f
def pow(A, n):
if n == 1: return A
if n & 1 == 0: return pow(mul(A, A), n/2)
else: return mul(A, pow(mul(A, A), (n-1)/2))
def fib(n):
if n < 2: return n
return pow((1,1,0), n-1)[0]
This calculates the nth Fibonacci number in O(log N) time, from the matrix equation
- <math>\begin{bmatrix} 1 & 1 \\ 1 & 0 \end{bmatrix}^n =
\begin{bmatrix} F\left(n+1\right) & F \left(n\right) \\
F\left(n\right) & F \left(n-1\right) \end{bmatrix}
<math> and by using exponentiating by squaring.
Scheme examples
Binary recursion, snippet
(define fibo
(lambda (x)
(if (< x 2)
x
(+ (fibo (- x 1)) (fibo (- x 2))))))
Runs in Θ(F(n)) time, which is Ω(1.6n).
Tail-end recursive, snippet
(define (fibo x)
(define (fibo-iter x a b)
(if (= x 0)
a
(fibo-iter (- x 1) b (+ a b))))
(fibo-iter x 0 1))
Runs in Θ(n) time.
Display all, snippet
(define (fibo-run a b) (display a) (newline) (fibo-run b (+ a b))) (define fibo-run-all (fibo-run 0 1)))
C/C++/Java example
Recursive snippet
int fib(int n) {
if (n < 2)
return n;
else
return fib(n-1) + fib(n-2);
}
Runs in Θ(F(n)) time, which is Ω(1.6n).
Ruby examples
def fib(num)
i, j = 0, 1
while i <= num
yield i
i, j = j, i + j
end
end
fib(10) {|i| puts i}
See also
- Fibonacci number
- Golden ratio
- Hello world program (Unrelated to the Fibonacci numbers, but contains many programming examples.)
External links
- Fibonacci series implementations and benchmark (http://www.inorg.chem.msu.ru/~cubbi/serious/fibonacci.html)
