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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude(X^2)138 ÷6 =22 * 23
Correct
Answer – 1. 23
Explanation:
(X^2)23 =22 * 23
X^2 = 529
X = 23Incorrect
Answer – 1. 23
Explanation:
(X^2)23 =22 * 23
X^2 = 529
X = 23 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude?% of 400 + (13)^2 = 285
Correct
Answer – 5. 29
Explanation:
4x = 285 – 169
x = 29Incorrect
Answer – 5. 29
Explanation:
4x = 285 – 169
x = 29 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude19, 10, 11, 18, ?, 97.5
Correct
Answer – 4. 38
Explanation:
19 * 0.5 + 0.5 = 10
10 * 1 + 1 = 11
11 * 1.5 + 1.5 = 18
18 * 2 + 2 = 38
38 * 2.5 + 2.5 = 97.5Incorrect
Answer – 4. 38
Explanation:
19 * 0.5 + 0.5 = 10
10 * 1 + 1 = 11
11 * 1.5 + 1.5 = 18
18 * 2 + 2 = 38
38 * 2.5 + 2.5 = 97.5 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeIn 2017, the total population of a City was 4800, out of which 40% were females. In 2018, the total population increased by 10% in comparison to the previous year. If the number of females remained the same in 2018, what was the percentage increase in the number of males in 2018 in comparison to 2017?
Correct
Answer – 4. 50/3%
Explanation:
Required % increase in male population = ((10*4800)*100}/(60*4800)}=50/3 %Incorrect
Answer – 4. 50/3%
Explanation:
Required % increase in male population = ((10*4800)*100}/(60*4800)}=50/3 % 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeAjay alone can do a work in 24 days. Time taken by Ajay in completing 1/3 of work is equal to the time taken by Bharat in completing 1/2 of work. In what time Ajay & Bharat together will complete the work(in Days)?
Correct
Answer – 4. 48/5
Explanation:
Time taken by Ajay in doing 1/3 work in 8 days
Time taken by Ajay in doing 1 work =24 days
Time taken by Bharat in doing work in 16 days
So (Ajay+Bharat)’s 1 day work = (16 *24)/(16 +24) = 48/5 daysIncorrect
Answer – 4. 48/5
Explanation:
Time taken by Ajay in doing 1/3 work in 8 days
Time taken by Ajay in doing 1 work =24 days
Time taken by Bharat in doing work in 16 days
So (Ajay+Bharat)’s 1 day work = (16 *24)/(16 +24) = 48/5 days 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the cost price of material P to that Q is 7:9. Material P was sold at a profit of 40 % & material Q was sold at a profit of 10%. If the total profit earned after selling both the materials (P & Q) is Rs 148, what is the difference between the cost price of materials P & Q?
Correct
Answer – 4. Rs 80
Explanation:
40 % of 7X +10 % of 9X= Rs 148
3.7X=148
Difference =(9X7X)=2X= (148*2X)/3.7X= Rs 80Incorrect
Answer – 4. Rs 80
Explanation:
40 % of 7X +10 % of 9X= Rs 148
3.7X=148
Difference =(9X7X)=2X= (148*2X)/3.7X= Rs 80 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA mixture of Lime and water in a container contains 28 litres Lime and 8 litres water. X litres Lime and X litre water are mixed to form a new mixture. If 40% of the new mixture is 20 litre. Find the value of X(in litre)
Correct
Answer – 1. 7
Quantity of new mixture = (28 + 8 + 2X) litre= (36 + 2X)litre
(36+2X) * 40/100=20
X=7Incorrect
Answer – 1. 7
Quantity of new mixture = (28 + 8 + 2X) litre= (36 + 2X)litre
(36+2X) * 40/100=20
X=7 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitudex² – y² = 112
x – y = 8Correct
Answer – 1. X > Y
Explanation:
x² – y² = 112
x – y = 8
(x + y) (x – y) = 112
(x + y) 8 = 112
x + y = 14
x – y = 8
x = 11 and y = 3Incorrect
Answer – 1. X > Y
Explanation:
x² – y² = 112
x – y = 8
(x + y) (x – y) = 112
(x + y) 8 = 112
x + y = 14
x – y = 8
x = 11 and y = 3 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeAnil covers a certain distance by travelling at a uniform speed of 120 kmph for 90 minutes. At what speed will he have to travel in order to cover the same distance in 1 hour 20 minutes?
Correct
Answer – 1. 135 kmph
Explanation:
Distance covered by Anil in 90 minutes =120 * 90/60=180 km
Required speed = 180/(4/3)=135 kmphIncorrect
Answer – 1. 135 kmph
Explanation:
Distance covered by Anil in 90 minutes =120 * 90/60=180 km
Required speed = 180/(4/3)=135 kmph 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIf a pipe P can fill a container 3 times faster than pipe Q. If both the pipes can fill the container in 32 minutes, then the slower pipe alone will be able to fill the container in?
Correct
Answer – 1. 128 minutes
Explanation :
Time is taken by pipe P = x
Time is taken by pipe Q = x/3
1/x + 3/x = 1/32
x = 128 minutesIncorrect
Answer – 1. 128 minutes
Explanation :
Time is taken by pipe P = x
Time is taken by pipe Q = x/3
1/x + 3/x = 1/32
x = 128 minutes
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