Comparison of topologies
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In topology and related areas of mathematics comparison of topologies refers to the fact that two topological structures on a given set may stand in relation to each other. The set of all possible topologies on a given set forms a partially ordered set. This order relation can be used to compare the different topologies.
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Definition
Let τ1 and τ2 be two topologies on a set X such that τ1 is contained in τ2:
- <math>\tau_1 \subseteq \tau_2<math>.
That is, every set open under τ1 is also open under τ2. Then the topology τ1 is said to be a coarser (weaker or smaller) topology than τ2, and τ2 is said to be a finer (stronger or larger) topology than τ1. If additionally
- <math>\tau_1 \neq \tau_2<math>
we say τ1 is strictly coarser than τ2 and τ2 is strictly finer than τ1.
The binary relation ⊆ defines a partial ordering relation on the set of all possible topologies on X.
N.B. There are some authors, especially analysts, who use the terms weak and strong with opposite meaning.
Examples
The finest topology on X is the discrete topology. The coarsest topology on X is the trivial topology.
In function spaces and spaces of measures there are often a number of possible topologies. See topologies on the set of operators on a Hilbert space for some intricate relationships.
All possible polar topologies on a dual pair are finer than the weak topology and coarser than the strong topology.
Properties
Let τ1 and τ2 be two topologies on a set X. Then the following statements are equivalent:
- τ1 ⊆ τ2
- the identity map idX : (X, τ2) → (X, τ1) is a continuous map.
- the identity map idX : (X, τ1) → (X, τ2) is an open map (or, equivalently, a closed map)
Two immediate corollaries of this statement are
- A continuous map f : X → Y remains continuous if the topology on Y becomes coarser or the topology on X finer.
- An open (resp. closed) map f : X → Y remains open (resp. closed) if the topology on Y becomes finer or the topology on X coarser.
One can also compare topologies using neighborhood bases. Let τ1 and τ2 be two topologies on a set X and let Bi(x) be a local base for the topology τi at x ∈ X for i = 1,2. Then τ1 ⊆ τ2 if and only if for all x ∈ X, each open set U1 in B1(x) contains some open set U2 in B2(x). Intuitively, this makes sense: a finer topology should have smaller neighborhoods.
Lattice of topologies
The set of all topologies on a set X together with the partial ordering relation ⊆ forms a complete lattice. That is, any collection of topologies on X have a meet (or infimum) and a join (or supremum). The meet of a collection of topologies is the intersection of those topologies. The join, however, is not generally the union of those topologies (the union of two topologies need not be a topology) but rather the topology generated by the union.
Every complete lattice is also a bounded lattice, which is to say that is has a greatest and least element. In the case of topologies, the greatest element is the discrete topology and the least element is the trivial topology.
See also
- Initial topology, the coarsest topology on a set to make a family of mappings from that set continuous
- Final topology, the finest topology on a set to make a family of mappings into that set continuous